Stitz-Zeager_College_Algebra_e-book

We get i1 1625 ma i2 125 ma i3 1125 ma and i4

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Unformatted text preview: ers t (d) Inconsistent (g) Inconsistent 3. (a) (−2, 7) (b) (1, 2, 0) (c) (−t + 5, −3t + 15, t) for all real numbers t (d) (2, −1, 1) (e) (1, 3, −2) (f) Inconsistent (g) (1, 3, −2) 1 (h) −3, 2 , 1 (i) (j) 12 3, 3, 1 51 11 19 13 t + 13 , − 13 t 4 + 13 , t for all real numbers t (k) Inconsistent (l) (4, −3, 1) (m) −2t − 35 , −t − 11 , t 4 2 for all real numbers t (n) (1, 2, 3, 4) 4. If t represents the amount (in pounds) of peanuts, then we need 1.5t − 7.5 pounds of almonds and 17.5 − 2.5t pounds of cashews. Since we can’t have a negative amount of nuts, 5 ≤ t ≤ 7. 5. Let x1 and x2 be the numbers of adults and children, respectively, in the Zahlenreich family and let x3 and x4 be the numbers of adults and children, respectively, in the Nullsatz family. The system of equations determined by the given information is 15x1 + 8x2 = 38 15x3 + 8x4 = 39 15x1 + 8x2 + 15x3 + 8x4 = 77 15x1 + 15x3 = 45 We subtracted the cost of the babysitter in E3 so the constant is...
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