Stitz-Zeager_College_Algebra_e-book

We have 7 any non terminating just argued that 09 1

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: is encouraged to check the units in this equation are the same on both sides. To get you started, the units on the ‘3’ is ‘hours.’ 540 Systems of Equations and Matrices amount of work Taylor does = rate of Taylor working · time Taylor spent working 1 garden = (rate of Taylor working) · (4 hours) So we have that the rate Taylor works is 14garden = 1 garden . We are also told that when working hours 4 hour together, Taylor and Carl can weed the garden in just 3 hours. We have: amount of work done together = rate of working together · time spent working together 1 garden = (rate of working together) · (3 hours) From this, we find the rate of Taylor and Carl working together is 13garden = 1 garden . We are asked hours 3 hour to find out how long it would take for Carl to weed the garden on his own. Let us call this unknown t, measured in hours (to be consistent with the other times given to us in the problem.) Then: amount of work Carl does = rate of Carl working · time Carl spent working 1 garden = (rate of Carl working) · (t hours) In order to find t, we need to find the rate of Carl working,...
View Full Document

This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

Ask a homework question - tutors are online