Stitz-Zeager_College_Algebra_e-book

We have the following theorem theorem 1111 suppose

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Unformatted text preview: e (ASS) case, the result is a quadratic equation whose variable is that of the missing side. If the equation has no positive real zeros then the information given does not yield a triangle. If the equation has only one positive real zero then exactly one triangle is formed and if the equation has two distinct positive real zeros then two distinct triangles are formed. Apply the Law of Cosines to exercises 2a, 2c and 2d above in order to demonstrate this result. 9. Discuss with your classmates why Heron’s Formula yields an area in square units even though four lengths are being multiplied together. 11.3 The Law of Cosines 11.3.2 781 Answers 1. (a) α ≈ 35.54◦ β ≈ 85.16◦ γ = 59.3◦ a=7 b = 12 c ≈ 10.36 (f) α ≈ 32.31◦ β ≈ 49.58◦ γ ≈ 98.21◦ a=7 b = 10 c = 13 (b) α = 104◦ β ≈ 29.40◦ γ ≈ 46.60◦ a ≈ 49.41 b = 25 c = 37 (g) Information does not produce a triangle (c) α ≈ 85.90◦ β = 8.2◦ γ ≈ 85.90◦ a = 153 b ≈ 21.88 c = 153 (h) α ≈ 83.05◦ β ≈ 87.81◦ γ ≈ 9.14◦ a = 300 b = 302 c = 48 (d) α ≈ 36.87◦ β ≈ 53.13◦ γ = 90◦ a=3 b=4 c=5 (i) α...
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This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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