Stitz-Zeager_College_Algebra_e-book

# We put theorem 107 to good use in the following

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Unformatted text preview: er-clockwise (π/6) = 12 of a revolution. Thus α is a Quadrant I angle. Coterminal 2π angles θ are of the form θ = α + 2π · k , for some integer k . To make the arithmetic a bit easier, we note that 2π = 12π , thus when k = 1, we get θ = π + 12π = 13π . Substituting 6 6 6 6 k = −1 gives θ = π − 12π = − 11π and when we let k = 2, we get θ = π + 24π = 25π . 6 6 6 6 6 6 π/ π 2. Since β = − 43 is negative, we start at the positive x-axis and rotate clockwise (42π3) = 2 of 3 a revolution. We ﬁnd β to be a Quadrant II angle. To ﬁnd coterminal angles, we proceed as π π π π before using 2π = 63 , and compute θ = − 43 + 63 · k for integer values of k . We obtain 23 , 10π 8π − 3 and 3 as coterminal angles. y y 4 4 3 3 2 2 1 −4 −3 −2 −1 −1 α= 1 2 3 4 −2 −3 −4 α= π 6 1 π 6 in standard position. x −4 −3 −2 −1 −1 π β = − 43 1 2 3 4 x −2 −3 −4 π β = − 43 in standard position. π 3. Since γ = 94 is positive, we rota...
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## This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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