Stitz-Zeager_College_Algebra_e-book

K 1 x 7 98 30x 1 4 o 0 2 3 3 27 p

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Unformatted text preview: as usual and get p−1 (x) = 5003 2x . The domain −1 should match the range of p, which is [1, 250], and as such, we restrict the domain of of p p−1 to 1 ≤ x ≤ 250. 2(220) 2. We find p−1 (220) = 500−3 = 20. Since the function p took as inputs the weekly sales and furnished the price per system as the output, p−1 takes the price per system and returns the weekly sales as its output. Hence, p−1 (220) = 20 means 20 systems will be sold in a week if the price is set at $220 per system. 2 − − − 3. We compute P ◦ p−1 (x) = P p−1 (x) = P 5003 2x = −1.5 5003 2x + 170 5003 2x − 150. 7 we obtain P ◦ p−1 (x) = − 2 x2 +220x − 40450 . After a hefty amount of Elementary Algebra, 3 3 To understand what this means, recall that the original profit function P gave us the weekly profit as a function of the weekly sales. The function p−1 gives us the weekly sales as a function of the price. Hence, P ◦ p−1 takes as its input a price. The function p−1 returns the weekly sales, which in turn is fed into P to return t...
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This note was uploaded on 05/03/2013 for the course MATH Algebra taught by Professor Wong during the Fall '13 term at Chicago Academy High School.

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