exam instructions_updated slides(1)[1]

Exam instructions_updated slides(1[1]

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Unformatted text preview: t) 2 10/13/2011 Binary to decimal Decimal to Binary (11100110)2 = 0 x 20 + 1 x 21 +1 x 22 + 0 x 23+ 0 x 24 + 1 x 25 + 1 x 26 + 1 x 27 = 0 + 2 + 4 + 0 + 0 + 32 + 64 +128 = (230)10 (101.101)2 = 1 x 20 + 0 x 21 + 1 x 22 + (1 x 2‐1 + 0 x 2‐2 + 1 x 2‐3) = 1 + 0 + 4 + (1/2 + 0 + 1/8) = (5.625)10 Binary addition • • • • • 0 + 0 = 0 1 + 0 = 1 0 + 1 = 1 1 + 1 = 10 1 + 1 + 1 = 11 Example 1 1001001 + 11001 1 11 Check: 1 0 0 1 0 0 1 0 0 1 1 0 0 1 (1001001)2 = 1 x 20 + 1 x 23+ 1 x 26 1 1 0 00 1 0 = 1 + 8 + 64 = (73)10 (11001)2 = 1 x 20 + 1 x 23+ 1 x 24 = 1 + 8 + 16 = (25)10 (1100010)2 = 1 x 21+ 1 x 25+ 1 x 26 = 2 + 32 + 64 = (98)10 73 + 25 = 98 3 10/13/2011 Binary Subtraction Binary Subtraction • Just like decimal numbers we can use borrow method for binary subtraction too. • But we can't subtract a larger number from a smaller one column wise. • For ex, consider 45 – 62 = ‐17. This cannot be done column wise. We need to identify the greater number. • The computer method is to represent negative numbers in "two's complement" form. • This allows us to directly subtract any pair of numbers, including greater from smaller and come up with the correct result. • Usually MSB is allotted for represe...
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This note was uploaded on 05/05/2013 for the course ELEC 1111 taught by Professor Jayashriravishankar during the One '11 term at University of New South Wales.

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