#4 Weak Acid Strong Base Titration

# #4 Weak Acid Strong Base Titration - Aaron King 660556233...

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Aaron King 660556233 Section 1 March 4, 2008 #4 Weak Acid-Strong Base Titration 1. mass KHP (g) mol KHP mL NaOH M NaOH Trial 1 0.4087 0.002001 16.48 0.1214 Trial 2 0.4050 0.001983 16.31 0.1216 Trial 3 0.3987 0.001952 16.21 0.1204 0.1211 . . × . × = . 0 4087gKHP16 48mL 1molKHP204 22gKHP 1000mL1L 0 1214M = + + M M1 M2 M33 = . + . + . M 0 1214M 0 1216M 0 1204M3 = . M 0 1211M 2. While it is difficult to determine the exact moment of the equivalence point, both trials appeared to have an equivalence point when the pH is around 8. 3. Both trial one and two had their equivalence point when about 21mL of NaOH was added. Therefore, the half-equivalence point would have occurred when 10.5Ml were added. Trial 1 half-equivalence point, pH≈4.6 Trial 2 half-equivalence point, pH≈4.5 At the half-equivalence point, pH=pKa because the concentration of the acid and its conjugate base are equal. Therefore the pKa of the acid is 4.6 for Trial 1 and 4.5 for Trial 2. By using the equation, pKa=-log(Ka), the Ka for Trial 1 is 2.51x10

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## This lab report was uploaded on 04/07/2008 for the course CHEM 1200 taught by Professor Mcintosh during the Spring '08 term at Rensselaer Polytechnic Institute.

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#4 Weak Acid Strong Base Titration - Aaron King 660556233...

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