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# ps1-06a - Beetles Alleles ‘C’#’c’ Black CC 125...

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Evolution Dr. Susan Kalisz Problem Set #1 January 26, 2006 1. a) Allele frequency BEFORE selection: Phenotype Genotype # Beetles # Alleles # ‘C’ # ‘c’ Black CC 130 2(130) 260 0 Brown Cc 215 2(215) 215 215 Grey cc 210 2(210) 0 420 Total 555 1110 475 635 Frequency of ‘C’ allele = p = 475/1110 = 0.428 Frequency of ‘c’ allele = q = 635/1110 = 0.572 b) Yes. The population was in Hardy-Weinberg equilibrium before selection because the population fits all criteria for the “null “model. This model states in order for a population to be in equilibrium the Hardy-Weinberg equation must be proven. With the above frequencies, it does equal 1. c) Genotype Absolute Fitness Relative Fitness Selection Coefficients CC 125/130 = 0.96 0.96/0.96 1 Cc 100/215 = 0.47 0.47/0.96 1 - hs Cc 100/210 = 0.48 0.48/0.96 1 - s d) Allele frequency AFTER selection: Phenotype Genotype

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Unformatted text preview: # Beetles # Alleles # ‘C’ #’c’ Black CC 125 2(125) 250 Brown Cc 100 2(100) 100 100 Grey cc 100 2(100) 200 Total 325 650 350 300 Frequency of ‘C’ allele = p = 350/650 = 0.538 Frequency of ‘c’ allele = q =300/650 = 0.462 Change in allele frequencies: Δ p = p1 – p0 = 0.538 - 0.428 = 0.11 Δ q = q1 – q0 = 0.462 - 0.572 = -0.11 2. The expected allele frequency of the “eats glucose and maltose” egm allele is: 3.5 x 10^-4 / 1 x 10^-3 = 0.35 3. μ = Mutation Rate s = Selection Strength q = Equilibrium Frequency of an Allele The q allele affects with a high value for μ and a low value for s would yield an extremely deleterious result. The value of q is either maintained at a relatively low value or no longer exists. 4) Attached...
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