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**Unformatted text preview: **= + = n so N, . 171 1 = n keeping extra figures. This horizontal force about must be balanced by the frictional force, which must then be 170 N to two figures. c) Setting the frictional force, and hence 1 n , equal to the maximum of 360 N and solving for the distance x along the ladder, ), N 740 )( 5 3 ( ) N 160 )( m 50 . 1 ( ) N 360 )( m . 4 ( x + = so x = 2.70 m, or 2.7 m to two figures....

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