problem11_22

University Physics with Modern Physics with Mastering Physics (11th Edition)

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11.22: From Eq. (11.10), ). m 1333 ( ) m 10 0 . 50 m)( 10 0 . 3 ( m) 200 . 0 ( 2 2 4 2 0 - - - = × × = = F F l F Y Then, N 0 . 25 = F corresponds to a Young’s modulus of N 500 and
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