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Higher 1A T2 2012 Solutions - !$#$ s = 4(0)2 1 = 1m $ v =...

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!!"!#!!$! &'()*+,- ! ." "/!" !" $" $$" $$$" %" &'()*+, ,-* ./**0 ,' 12 3($,.4 &'(.,!(, !55*6*+!,$'(4 5" 0" $" $$" *" $" 7, ,-* .!8* )*6'5$,9 !. ,-* 5!+: !, ! ,!(;*(, ,' ,-* 53+)* <'66'=*0 %9 ,-* 5!+4 ) > [email protected] 8. C? D) $( 0$*5,$'( .-'=( $( 0$!;+!8 !%')*" $$" $$$" $)" s = 4(0) 2 + 1 = 1 m v = ds dt = 8 tms 1 a = d 2 s dt 2 = 8 ms 2 50 km/hr = 50 × 10 3 3600 = 13 . 9 ms 1 t = v a = 13 . 98 = 1 . 7 s x = x 0 + v 0 t + 1 2 at 2 = 1 + 0 × 8 + 1 2 × 8 × 1 . 7 2 = 13 m a c = v 2 r = 13 . 9 2 30 = 6 . 4 ms 2 towards the center of the curve y = 1 2 a y t 2 t = 2 y g = 2 × 1 . 4 9 . 8 = 0 . 53 s x = v x 0 t = 13 . 9 × 0 . 53 = 7 . 4 m v y = a y t = 9 . 8 × 0 . 53 = 5 . 2 ms 1 v = v 2 x + v 2 y = 13 . 9 2 + 5 . 2 2 = 15 ms 2 To work out direction need to calculate θ tan θ = v y v x = 5 . 2 13 . 9 θ = 20 . 5 o below horizontal
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!"#$%&'( * ++,+ -. ./+. !" $" % $$" $$$" $&" '" $" $$" (" $" $$" $$$" P = F A P f = P i + mg A = 1 . 17 × 10 5 + 5 × 9 . 8 12 . 0 × 10 4 = 1 . 58 × 10 5 Pa quickly adiabatic PV γ = const γ = C P C V = R + 1 2 fR 1 2 fR = 5 3 P i V 5 / 3 i = P f V 5 / 3 f 1 . 17 × 10 5 × (0 . 20 × 12 . 00 × 10 4 ) 5 / 3 = 1 . 58 × 10 5 × ( h f × 12 × 10 4 ) 5 / 3 ( h f × 12 × 10 4 ) 5 / 3 = 8 . 8635 × 10 7 h f × 12 × 10 4 = 2 . 004 × 10 4 h f = 16 . 7 cm PV = const P i V i = P f V f 1 . 17 × 10 5 × 0 . 20 × 12 . 00 × 10 4 = 1 . 58 × 10 5 × h f × 12 × 10 4 h f = 14 . 8 cm P = kA | dT dx | P is constant along the rod P = 385 × 10 × 10 4 × (70
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