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# Por otro lado t t 4t t derivando sucesivamente 0 0

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Unformatted text preview: e =1. Por otro lado: ψ t ψ´ t 4t t , derivando sucesivamente: ψ´ 0 0; ψ´´´ t 4 · 3 · 2t ψ´´´ 0 0 ψ´´ t 4 · 3t ψ´´ 0 0; t 4·3·2 ·1 0 4! Luego vemos que 4 es el orden de la derivada distinta de cero (n=4), que su valor es 4! y según las notas vemos que dados los resultados anteriores estamos en el caso en el que 0 0 y f(t) es distinto de 0 y finito, por tanto podemos escribir que: ! Г identificando los términos obtenidos vemos que: 4! 24 Г 1 4 4 1 · Con lo que ya tenemos el valor de la integral 1 4 , pero como queremos saber : Re Por otro lado: I(x)= (...
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