Unformatted text preview: then N, 4800 N 1200 N 3600 = + so the net force on the rear wheels is N, 10 36 . 1 N 4800 N 8820 4 × = + again to three figures. b) Now we want a shift of N 10,780 away from the front axle. Therefore, N 780 , 10 m 00 . 3 m 00 . 1 = W and so N. 340 , 32 = w...
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 Force, net force, rear wheels

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