problem11_51

University Physics with Modern Physics with Mastering Physics (11th Edition)

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11.51: a) Take torques about her hind feet. Her fore feet are 0.72 m from her hind feet, and so her fore feet together exert a force of N, 9 . 73 m) 72 . 0 ( m) 28 . 0 ( N) 190 ( = so each foot exerts a force of 36.9 N, keeping an extra figure. Each hind foot then exerts a force of 58.1 N.
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Unformatted text preview: b) Again taking torques about the hind feet, the force exerted by the fore feet is N, 1 . 105 m 72 . m) 09 . ( N) 25 ( m) 28 . ( N) 190 ( = + so each fore foot exerts a force of 52.6 N and each hind foot exerts a force of 54.9 N....
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