problem11_51

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
11.51: a) Take torques about her hind feet. Her fore feet are 0.72 m from her hind feet, and so her fore feet together exert a force of N, 9 . 73 m) 72 . 0 ( m) 28 . 0 ( N) 190 ( = so each foot exerts a force of 36.9 N, keeping an extra figure. Each hind foot then exerts a force of 58.1 N.
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: b) Again taking torques about the hind feet, the force exerted by the fore feet is N, 1 . 105 m 72 . m) 09 . ( N) 25 ( m) 28 . ( N) 190 ( = + so each fore foot exerts a force of 52.6 N and each hind foot exerts a force of 54.9 N....
View Full Document

This document was uploaded on 02/05/2008.

Ask a homework question - tutors are online