problem11_53

University Physics with Modern Physics with Mastering Physics (11th Edition)

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11.53: a) Take the torque exerted by 2 F to be positive; the net torque is then , sin sin ) ( sin ) ( 2 1 φ Fl l x F x F = + + - where F is the common magnitude of the forces. b) m, N 3 . 25 37 sin ) m 0 . 3 )( N 0 . 14 ( 1 - = ° - = τ keeping an extra figure, and m, N 9 . 37 37 sin ) m 5 . 4 )( N 0 . 14 ( 2 = ° = τ and the net torque is m. N 6 . 12 About point P, m, N 3 . 25 ) 37 )(sin m 0 . 3 )(
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Unformatted text preview: N . 14 ( 1 = = and m, N 6 . 12 ) 37 )(sin m 5 . 1 )( N . 14 ( 2 -= -= and the net torque is m. N 6 . 12 The result of part (a) predicts , 37 sin ) m 5 . 1 )( N . 14 ( the same result....
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This document was uploaded on 02/05/2008.

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