problem11_60

University Physics with Modern Physics with Mastering Physics (11th Edition)

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11.60: a) The center of mass of the beam is 1.0 m from the suspension point. Taking torques about the suspension point, ) m 00 . 2 )( N 100 ( ) m 00 . 1 )( N 0 . 140 ( ) m 00 . 4 ( = + w (note that the common factor of sin
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Unformatted text preview: ° 30 has been factored out), from which N. . 15 = w b) In this case, a common factor of sin ° 45 would be factored out, and the result would be the same....
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This document was uploaded on 02/05/2008.

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