MCV4U_Unit 2_Assignment for Grading_Zainab Shibly.pdf - 1 a...

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1.a)?(?) = 13?4− 7?3+ 5?2+ 11? + 75?(?) = 4(13?3) − 3(7?2) + 2(5?) + 1(11) + 0?(?) = 52?3− 21?2+ 10? + 11b)𝐹(?) = (?3+ 2?2+ 4)(?4− 3)?(?) = ?3+ 2?2+ 4?(?) = 3?2+ 4??(?) = ?4− 3?(?) = 4?3𝑭(?) = ?(?)?(?) + ?(?)?′(?)𝐹(?) = (3?2+ 4?)(?4− 3) + (?3+ 2?2+ 4)(4?3)𝐹(?) = 3?6− 9?2+ 4?5− 12? + 4?6+ 8?5+ 16?3𝐹(?) = 7?6+ 12?5+ 16?3− 9?2− 12?c)𝐹(?) =3?2−6?+74?−1?(?) = 3?2− 6? + 7?(?) = 6? − 6?(?) = 4? − 1?(?) = 4𝑭(?) =?(?)?(?)−?(?)?′(?)[?(?)]?𝐹(?) =(6?−6)(4?−1)−(3?2−6?+7)(4)(4?−1)2𝐹(?) =(24?2−6?−24?+6)−(12?2−24?+28)(4?−1)2𝐹(?) =24?2−6?−24?+6−12?2+24?−28(4?−1)2𝐹(?) =12?2−6?−22(4?−1)2d)?(?) = (4?3− 7?)7?(?) = 7(4?3− 7?)6(12?2− 7)e)12 = ?2+ ?2?2+ ?2= 02? + 2?(?) = 02?(?) = −2??=−2?2??=−??
?2= 12 − ?2? = √12 − ?2∴ ?=−?√12−?2f)?(?) = 156?(?) = 0g)𝐹(?) = (1 − 3?)2(?2− 2)3?(?) = (1 − 3?)2?(?) = [2(1 − 3?)][−3] = (−3)(2 − 6?) = −6 + 18??(?) = (?2− 2)3?(?) = [3(?2− 2)2][2?] = 2?(3(?2− 2)3) = 6?(?2− 2)2= 6?5− 24?3+ 24?𝑭(?) = ?(?)?(?) + ?(?)?′(?)𝐹(?) = (−6 + 18?)(?2− 2)3+ (1 − 3?)2(6?5− 24?3+ 24?)h)𝐹(?) = (2?2+13?3+1)2=4?4+4?2+19?6+6?3+1 ?(?) = 4?4+ 4?2+ 1?(?) = 4(4?3) + 2(4?) = 16?3+ 8??(?) = 9?6+ 6?3+ 1?(?) = 6(9?5) + 3(6?2) = 54?5+ 18?2𝑭(?) =?(?)?(?)−?(?)?′(?)[?(?)]?𝐹(?) =(16?3+8?)(9?6+6?3+1)−(4?4+4?2+1)(54?5+18?2)(9?6+6?3+1)2𝐹(?) =(144?9+ 96?6+ 16?3+ 72?7+ 48?4+ 8?) − (216?9+ 216?7+ 54?5+ 72?6+ 724+ 18?2)(9?6+ 6?3+ 1)2𝐹(?) =144?9+72?7+96?6+48?4+16?3+8?−216?9−216?7−72?6−54?5−724−18?2(9?6+6?3+1)2𝐹(?) =−72?9−144?7+24?6−54?5−24?4+16?3−18?2+8?(9?6+6?3+1)22.?(?) = (3?2− 7? + 4)8?(?) = [8(3?2− 7? + 4)7][2(3?) − 7]?(?) = (24?2− 56? + 32)7(6? − 7)?"(?) = [7(24?2− 56? + 32)6(2(24?)) − 56)][6] ?"(?) = (168?2− 392? + 224)6(48? − 56)(6) ?"(?) = (168?2− 3892? + 224)6(288? − 336)3.?(?) = 12?10− 3?7+ 4?5+ 5?2+ 6 ?(?) = 10(12?9) − 7(3?6) + 5(4?4) + 2(5?) + 0
?(?) = ?????− ????+ ????+ ??? ?"(?) = 9(120?8) − 6(21?5) + 4(20?3) + 10?"(?) = ??????− ?????+ ????+ ???′′′(?) = 8(1080?7) − 5(1264) + 3(80?2) + 0?′′′(?) = ??????− ?????+ ?????4.? = ?2− 2? + 3; 𝑃?𝑖??: (2,3)?(?) = 2? − 2? = ?′(2)?(2) = 2(2) − 2 = 2∴ ? = 2? = ?(? − ?1) + ?1? = 2(? − 2) + 3? = 2? − 4 + 3? = 2? − 1The equation of the tangent line to the curve ? = ?2− 2? + 3at the point (2,3) is ? = 2? − 1. 5.? = −?2+ 3? + 4; 𝑆???? = 5?(?) = 2(−?) + 3?(?) = −2? + 3? = 55 = −2? + 3−2? = 2? = −1? = −(−1)2+ 3(−1) + 4? = −1 − 3 + 4? = 0Point: (−1,0)The slope of the tangent line is 5 on the on the parabola ? = −?2+ 3? + 4at the point (-1,0).

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