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**Unformatted text preview: **, l . 2 tan n and ) ( 2 wx l w l x l w l w fl + =-+ = In terms of the coefficient of friction , s . tan 2 2 3 tan ) ( 2 2 s x l x l x x l n f l l +-= +-+ = Solving for x , cm. 2 30 tan tan 3 2 s s . l x = +-c) In the above expression, setting gives for solving and cm 10 s = x . 625 . 20 1 tan ) 20 3 ( s = +-l l...

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