problem11_66

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
11.66: a) Taking torques about the right end of the stick, the friction force is half the weight of the stick, = 2 w f Taking torques about the point where the cord is attached to the wall (the tension in the cord and the friction force exert no torque about this point),and noting that the moment arm of the normal force is . 22 ) 40 . 0 ( arctan so 0.40, tan Then, tan , tan 2 ° = < < = = θ n l n f w b) Taking torques as in part (a), and denoting the length of the meter stick as
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: , l . 2 tan n and ) ( 2 wx l w l x l w l w fl + =-+ = In terms of the coefficient of friction , s . tan 2 2 3 tan ) ( 2 2 s x l x l x x l n f l l +-= +-+ = Solving for x , cm. 2 30 tan tan 3 2 s s . l x = +-c) In the above expression, setting gives for solving and cm 10 s = x . 625 . 20 1 tan ) 20 3 ( s = +-l l...
View Full Document

This document was uploaded on 02/05/2008.

Ask a homework question - tutors are online