problem11_73

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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11.73: a) There are several ways to find the tension. Taking torques about point B (the force of the hinge at A is given as being vertical, and exerts no torque about B ), the tension acts at distance 2 2 ) m 00 . 2 ( ) m 00 . 4 ( + = r 47 . 4 = m and at an angle of . 6 . 56 4.00 2.00 arctan 30 ° = + ° = φ Setting N 268 gives for solving and ) m 00 . 2 ( N) 500 ( sin = = T T φ Tr . b) The hinge at A is given as exerting no horizontal force, so taking torques about point , D the lever arm for the vertical force at point m, 4.31 30.0 tan
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Unformatted text preview: m 00 . 4 ( m) (2.00 is = ° + B so the horizontal force at N. 232 m 31 . 4 ) m 00 . 2 ( N) 500 ( is = B Using the result of part (a), however, N 232 30.0 cos N) 268 ( = ° In fact, finding the horizontal force at B first simplifies the calculation of the tension slightly. c) N. 366 . 30 sin ) N 268 ( ) N 500 ( = °-Equivalently, the result of part (b) could be used, taking torques about point , C to get the same result....
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• NoProfessor
• Force, Simple machine, horizontal force, Tr sin

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