11.80:
a) The torque exerted by the cable about the left end is
θ
TL
sin
. For any angle
,
sin
)
180
(
sin
,
θ
θ
=

°
θ
so the tension
T
will be the same for either angle. The horizontal
component of the force that the pivot exerts on the boom will be
θ
T
T
θ
T
cos
)
180
(
cos
or
cos

=

°
. b) From the result of part (a),
,
α
sin
1
θ
T
and this
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 Force, Sin, TL sin

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