11.80: a) The torque exerted by the cable about the left end is θ TL sin . For any angle , sin ) 180 ( sin , θ θ =-° θ so the tension T will be the same for either angle. The horizontal component of the force that the pivot exerts on the boom will be θ T T θ T cos ) 180 ( cos or cos-=-° . b) From the result of part (a), , α sin 1 θ T and this
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