Unformatted text preview: inforcement Individual Layers (Name = bottom; Number of Bars = 3, Select 2 (ii)
(iv) bar by area, Bar Area = 314 mm , Dist. From bottom = 65 mm, Select “Add” and then “OK” To define material properties of steel: Define Material Properties Reinforcement Detailed fy (input “Yield Strength” = 400, Ultimate Strength” = 400) Select the cross‐section icon to review input and calculated values Solve “Full or Sectional Response” to solve Problem 2. When asked about leaving off tension stiffening, select “Yes” May wish to Select “More Detail” a Few Times, Review effect of this on the predicted response Problem 3: The My and φy of this section with three 20 mm diameter bars Use from problem #2, run the sectional analysis a few times (using the more detail feature), scroll along Load‐
Deformation response to find location where the reinforcement has yielded (th...
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This note was uploaded on 06/15/2013 for the course CEE 461 taught by Professor Abrams during the Fall '08 term at University of Illinois, Urbana Champaign.
- Fall '08