Unformatted text preview: θ g ρl cot ) 2 ( and the change in length is . cot ) 2 ( 2 θ Υ g ρl d) Using the numerical values, the stress is 5 10 4 . 1 × Pa and the change in length is m. 10 2 . 2 6× e) The stress is proportional to the length and the change in length is proportional to the square of the length, and so the quantities change by factors of 2 and 4....
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 Force, 6 m, 10 5 Pa, mg mg cot

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