*This preview shows
page 1. Sign up
to
view the full content.*

**Unformatted text preview: **g l cot ) 2 ( and the change in length is . cot ) 2 ( 2 g l d) Using the numerical values, the stress is 5 10 4 . 1 Pa and the change in length is m. 10 2 . 2 6- e) The stress is proportional to the length and the change in length is proportional to the square of the length, and so the quantities change by factors of 2 and 4....

View
Full
Document