Limiting Reactants - Limiting Reactants and Percent Yield I Limiting Reactant A reactant that limits the amount of other reactants that can combine and

# Limiting Reactants - Limiting Reactants and Percent Yield I...

• Notes
• 2

This preview shows page 1 - 2 out of 2 pages.

Limiting Reactants and Percent Yield I. Limiting Reactant A. reactant that limits the amount of other reactants that can combine and limits the formation of the product C. Divide the mass of each reactant with the number of molar masses B. Ex. 2H 2 + O 2 2H 2 O with 10 grams of each hydrogen and oxygen 1. Hydrogen: 10 grams / 2 molar masses = 10/4 = 2.5 2. Oxygen: 10 grams / 1 molar mass = 10/32 = .31 (limiting reactant) 3. Remember to use limiting reactant when using Stoichiometry to find moles/ mass I. Conversion of mole to mass II. Use molar mass from periodic table

Subscribe to view the full document.

Unformatted text preview: III. 1. 10 mol O 2 x (2 moles H 2 / 1 mole O 2 ) x (2 grams/ 1 mol H 2 ) = 40 g H 2 IV. Conversion of mass to moles A. Use the inverse of the conversion factor… e.g. (1 mol H 2 / 2 grams) 1. 10 grams H 2 x (1 mol H 2 / 2 grams) = 5 mol V. Conversion from mass to mass A. grams of A moles of A moles of B grams of B 1. ex. 10 grams H 2 5 mol H 2 2.5 mol O 2 80 grams O 2 II. Percent Yield A. Theoretical Yield- the maximum amount of a product that can be produced from a given amount of reactant...
View Full Document

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern

Ask Expert Tutors You can ask 0 bonus questions You can ask 0 questions (0 expire soon) You can ask 0 questions (will expire )
Answers in as fast as 15 minutes