**Unformatted text preview: **III. 1. 10 mol O 2 x (2 moles H 2 / 1 mole O 2 ) x (2 grams/ 1 mol H 2 ) = 40 g H 2 IV. Conversion of mass to moles A. Use the inverse of the conversion factor… e.g. (1 mol H 2 / 2 grams) 1. 10 grams H 2 x (1 mol H 2 / 2 grams) = 5 mol V. Conversion from mass to mass A. grams of A moles of A moles of B grams of B 1. ex. 10 grams H 2 5 mol H 2 2.5 mol O 2 80 grams O 2 II. Percent Yield A. Theoretical Yield- the maximum amount of a product that can be produced from a given amount of reactant...

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- Fall '08
- Young
- Mole, Stoichiometry, Molar masses