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Unformatted text preview: I x 2RCube + I x (2RCord + 2RCable + RCar) = I x 2RCube + VCube/Cord 124V = 12A x 2RCube + 114 RCube = 0.4166 Ω c) P= IV; V=IR P = I2R PCable = I2R = (12A)2 x (2 x RCable) = 11.95 W PCord = I2R = (12A)2 x (2 x RCord) = 36 W PCube = I2R = (12A)2 x (2 x RCube) = 120 W 7. Standard units are: Power = Watt [W] Current = Ampere [A] Voltage = Volt [V] Energy = Joules [J] kWh is a unit of energy. Power = I*V = Energy/time ...
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This note was uploaded on 06/25/2013 for the course ECE 100 taught by Professor Pister during the Spring '13 term at University of California, Berkeley.

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