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# 1 432 1 2 43 i 1 i 2

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Unformatted text preview: p‬‬ ‫המקיים את שתי המשוואות הבאות:‬ ‫‪π = πA‬‬ ‫‪π = πB‬‬ ‫לפי סעיפים א' ו ב', הפתרון היחיד הינו:‬ ‫)‬ ‫1‬ ‫5‬ ‫, , , (= ‪π‬‬ ‫2‬ ‫5‬ ‫1‬ ‫5‬ ‫1‬ ‫5‬ ‫סעיף‬ ‫סעיף ה:‬ ‫מהמרקוביות של התהליך ‪ ,X‬נובע שגם התהליך בזמנים זוגיים ..., 4 ‪ X 0 , X 2 , X‬וגם התהליך בזמנים אי-זוגיים ..., 5 ‪X 1 , X 3 , X‬‬ ‫הינם תהליכים מרקוביים.‬ ‫נראה כעת שתהליך ..., 4 ‪X 0 , X 2 , X‬‬ ‫הינו מרקובי הומוגני:‬ ‫2‬ ‫)..., ‪P ( X 2 k = j | X 2 k −2 = i, X 2 k −4 = l‬‬ ‫4‬ ‫)..., ‪= ∑ P( X 2 k = j | X 2 k −1 = k , X 2 k −2 = i, X 2 k −4 = l ,...) ⋅ P( X 2 k −1 = k | X 2 k −2 = i, X 2 k −4 = l‬‬ ‫1= ‪k‬‬ ‫4‬ ‫‪= ∑ Aik Bkj = [ AB ]ij‬‬ ‫1= ‪k‬‬ ‫כלומר, התהליך בזמנים זוגיים...
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