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Name _________________________________________________ Course/Year ___________ Student No: ____________________ Subject/Section ___________ Group No._____ Seat No. _____ Date of Performance: ____________________ Date of Submission _____________________________________ Grading Rubrics SCORE Analysis (20 points) Conclusion (20 points) Data Sheet (5 points) Safe Assign (10 points) Presentation (5 points) Group Report (40 points) TOTAL _________________________________ Instructor Experiment 101 Newton’s Second Law of MotionAaron Paul C TayagECE - 12020100648Phys101L B34Dec 4, 2020Dec 4, 2020Dec 9, 2020Carlos III Baldo
2 EXPERIMENT NO. 101 NEWTON’S SECOND LAW OF MOTIONINTRODUCTION Newton’s second law of motion states that a net force is required for a body to have acceleration. If a net force is applied on a body, the body will accelerate in the direction of the net force. The acceleration of the body is also directly proportional to the net force but inversely proportional to its mass. This is Newton’s second law of motion. In this experiment, we will verify the relationships between a body’s acceleration and net force, and between acceleration and mass. OBJECTIVES 1.To verify the direct proportionality of acceleration and net force if the mass of the body is constant. 2.To verify the inverse proportionality of acceleration and mass if the net force is constant. MATERIALS 1 pc dynamics track with pulley 1 pc dynamics cart 1.5 m string 2 pcs photogates 1 pc smart timer 1 pc set of weights 1 pc weight hanger THEORY Newton defined momentum ࠵?as the product of mass and velocity. The change in momentum ࠵?࠵?is brought about by the impulse (࠵? = ࠵?net࠵?࠵?)acting on the body,࠵?net࠵?࠵? = ࠵?࠵?(eqn. 1)
3 As ࠵?࠵?approaches zero, the instantaneous rate of change of momentum is,࠵?net= lim࠵?࠵?→0࠵?࠵?࠵?࠵?=dPdt=࠵?(mv)dt(eqn. 2)Since for most object, mass is constant, ࠵?net= ࠵?dvdt(eqn. 3)Newton’s second law of motion is mathematically expressed as࠵?net= ma(eqn. 4)In Figure 1, the cart of mass ࠵?1is accelerating due to the tension ࠵?. From Newton’s second law࠵? = ࠵?1࠵?The hanging mass ࠵?2