D f 4 c 4 2 for some 0 c 2 therefore 4 64 f

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ( x) has a relative maximum at x = 2. (c) f (0) ≈ T (0) = 7 − 9 ( −2 ) − 3 ( −2 ) = −5 . We do not have enough information to 2 3 determine whether x = 0 is a critical number for f ( x) . For example, the whole family of functions g ( x) = T ( x) + C ( x − 2 ) , where C is any constant, has the same 4 third-degree Taylor polynomial T ( x) . f ( x) could be any one of these functions. One of these functions has a critical number at x = 0 — when 2 3 g ′(0) = −18 ⋅ ( −2 ) − 3 ⋅ 3 ( −2 ) + 4C ( −2 ) = 0 — others don’t. (d) f (4) ( c ) 4 ( −2 ) for some 0 ≤ c ≤ 2 . Therefore, 4! 64 f (0) − (...
View Full Document

This note was uploaded on 07/07/2013 for the course MATH AP taught by Professor Mr.snickles during the Fall '11 term at Benjamin N Cardozo High School.

Ask a homework question - tutors are online