Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

Updated On: 12-9-2020

Apne doubts clear karein ab Whatsapp par bhi. Try it now.

CLICK HERE

Loading DoubtNut Solution for you

Watch 1000+ concepts & tricky questions explained!

32.2 K+

1.6 K+

Text Solution

Answer :

N/aSolution :

Let A,B and C are the events of drawing first second and third red balls respectively. <br> `:.` Required probability `P(AnnBnnC)` <br> `=P(A).P(B//A).P(C//AnnB)` <br> Now `P(A)=(.^(5)C_(1))/(.^(12)C_(1))=5/12` <br> After drawing first red ball, remaining balls red `=4` black `=4` white `=3` <br> Total balls `=11` <br> `:.P(B//A)=(.^(4)C_(1))/(.^(11)C_(1))=4/11` <br> After drawing second red ball, remaining balls red `=3`, black `=4`, white` =3` <br> Total balls `=10` <br> `:. P(C//AnnB)=(.^(3)C_(1))/(.^(10)C_(1))=3/10` <br> `P(AnnBnnC)=P(A).P(B//A).P(C//AnnB)` <br> `=5/12xx4/11xx3/10=1/22` **Introduction and definition**

**Various terms learned in earlier classes**

**Verbal description of set and equivalent set theory notation and proof with venn diagram**

**Probability of an event: definition**

**What is the probability that four 'S' comes consecutively in the word 'MISSISSIPPI` when rearranged?**

**Compound events and definition of conditional probability**

**A die is thrown twice and the sum of the numbers appearing is observed to be 6. What is the conditional probability that the number 4 has appeared at least once?**

**Multiplication Theorems on Probability**

**A bag contains 5 white; 7 red and 8 black balls. If four balls are drawn one by one without replacement; find the probability of getting all white balls.**

**Addition Theorem Of Probability**