precalculus solutions 1.2 #3

precalculus solutions 1.2 #3 - Precalculus Lesson 1.2...

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Precalculus Lesson 1.2 Homework Packet page 22 #15-20 Worked out solutions 15. 2 ( ) 3 2 f x x = + appears even Prove: ( ) ( ) f x f x - = ( ) f x - = 2 2 3( ) 2 3 2 x x - + = + ( ) f x = f is even 16. 2 ( ) 2 f x x x = - appears neither Prove: ( ) ( ) f x f x - ( ) f x - = 2 2 ( ) 2( ) 2 x x x x - - - = + ( ) f x f is not even Prove: ( ) ( ) f x f x - ≠ - from above we know that ( ) f x - = 2 2 x x + ( ) f x - = 2 2 [ 2 ] 2 x x x x - - = - + ( ) ( ) f x f x - ≠ - f is not odd 17. 2 2 2 ( ) 16 x m x x = - appears even Prove: ( ) ( ) m x m x - = 2 2 2 2 2( ) 2 ( ) ( ) ( ) 16 16 x x m x m x x x - - = = = - - - m is even 18. 2 2 ( ) 4 x c x x = + appears even Prove: ( ) ( ) c x c x - = 2 2 2 2 ( ) ( ) ( ) ( ) 4 4 x x c x c x x x - - = = = - + + c is even
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19. 2 2 2 ( ) ( 5) 2 10 25 2 12 25 f x x x x x x x x = - - = - + - = - + appears neither Prove: ( ) ( ) f x f x - 2 2 ( ) ( ) 12( ) 25 12 25 ( ) f x x x x x
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precalculus solutions 1.2 #3 - Precalculus Lesson 1.2...

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