final-201-10-sol

# 46 10 rather than the four term expression given in

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Unformatted text preview: 10 · rather than the four term expression given in Table B.2 If a physical value you need (heat capacity, Antoine Equation parameter, etc.) lies outside the range specified in the text, you may use it regardless of the temperature. 1) (25 pts) You have a manometer attached to a piece of equipment as shown below. P P = 760 mm Hg ρ1 ρ2 25 cm 30 cm 45o 40 cm 30 10 cm o The densities of the two fluids in the manometer are: ρ1 = 1.5 g/cm3 and ρ2 = 2.5 g/cm3. What is the gauge pressure in the piece of equipment? SOLUTION The angle of inclination makes no difference in the problem. So adding up the pressures on each leg of the manometer gives 10 30 15 10 We could enter all of the known values in m, kg and s to get 1500 9.81 0.1 760 2500 2500 9.81 9.81 1500 9.81 0.1 0.3 0.15 or 1471.5 7357.5 · 760 11.04 760 · 2207.25 55.19 16.56 · 2452.5 18.40 · Thus 16.56 18.40 31.3 11.04 55.19 Another way would be to convert each fluid depth to an equivalent depth of mercury using the relationship 13.6 This gives 11.03 55.15 16.54 18.38 or 16.54 18.38 31.3 11.03 55.15 2) (15 pts)...
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## This note was uploaded on 07/24/2013 for the course CHE 321 taught by Professor Suha during the Fall '08 term at Washington State University .

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