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final-201-10-sol

6 this gives 1103 5515 1654 1838 or 1654 1838

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Unformatted text preview: Consider the two-stage, vapor/liquid separation process shown below m1 = 100 xA1 = 0.80 xB1 = 0.15 xC1 = 0.05 m3 = 125 xA3 = 0.30 xB3 = 0.30 xC3 = 0.40 m2 = xA2 = xB2 = xC2 = 1 3 2 Stage 1 Stage 2 6 4 m6 = xA6 = xB6 = xC6 = 5 m4 = 200 xA4 = 0.10 xB4 = 0.40 xC4 = 0.50 m5 = xA5 = xB5 = xC5 = where the m’s are masses and the x’s are mass fractions of the three components (A, B, and C). Determine the mass of stream 6 and its composition. SOLUTION Forget about the inner streams but do balances around the entire system (streams 1, 3, 4, and 6). An overall balance would give 100 200 125 175 A balance on species A gives 100 . 80 200 . 10 80 125 . 30 20 37.5 175 175 0.357 A balance on species B gives 100 . 15 200 . 40 125 . 30 175 15 80 37.5 175 0.329 Since the sum of the mass fractions must equal 1.0 you get in stream 6 1.0 1.0 0.357 0.314 0.329 3) (30 pts) Large areas of the Hanford area soil are contaminated with carbon tetrachloride. Wells drilled into the soil to monitor the presence of carbon tetrachloride have air that comes out of the well when a low pressure area moves into the area....
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