problem12_53

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
12.53: a) From Eq. (12.14), , m 10 492 . 7 2 s 86,164 kg) 10 (5.97 ) kg m N 10 673 . 6 ( 2 3 22 2 24 2 2 11 2 E 3 × = × × = = - π π T Gm r and so m. 10 58 . 3 7 E × = - = R r h Note that the period to use for the earth’s rotation
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: is the siderial day, not the solar day (see Section 12.7). b) For these observers, the satellite is below the horizon....
View Full Document

Ask a homework question - tutors are online