problem12_54

University Physics with Modern Physics with Mastering Physics (11th Edition)

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12.54: Equation 12.14 in the text will give us the planet’s mass: P 2 3 2 GM r T π = P 3 2 2 4 GM r T π = 2 3 2 2 11 3 6 5 2 2 3 2 P s) 10 8 . 5 )( kg m N 10 673 . 6 ( m) 10 80 . 4 m 10 75 . 5 ( 4 4 × × × + × = = - π π GT r M , kg 10 731 . 2 24 × = or about half earth’s mass. Now we can find the astronaut’s weight on the surface (The landing on the north
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  • North Pole, South Pole, 2 kg, 105 m, 85.6 kg

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