problem12_57

University Physics with Modern Physics with Mastering Physics (11th Edition)

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12.57: a) The satellite is revolving west to east, in the same direction the earth is rotating. If the angular speed of the satellite is s ω and the angular speed of the earth is , E ω the angular speed rel ω of the satellite relative to you is . E s rel ω ω ω - = ( 29 ( 29 ( 29 h rev h 12 rev 1 12 1 rel = = ω ( 29 h rev 12 1 E = ω ( 29 s rad 10 2.18 h rev -4 8 1 E rel s × = = + = ω ω ω r v m r mm G m E 2 2 says = = a F m 10 03 . 2 ; gives this with and 7 2 E 3 E 2 × = = = = r ω Gm r r v r Gm v ϖ This is the radius of the satellite’s orbit. Its height
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Unformatted text preview: h above the surface of the earth is m. 10 39 . 1 7 =-= E R r h b) Now the satellite is revolving opposite to the rotation of the earth. If west to east is positive, then ( 29 h rev 12 1 rel-= ( 29 s rad 10 7.27 h rev-5 24 1 E rel -=-= + = s m 10 59 . 3 and m 10 22 . 4 gives 7 7 2 E 3 = = = h r Gm r...
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This document was uploaded on 02/05/2008.

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