problem12_60

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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12.60: (a) Get g on Mongo: It takes 4.00 s to reach the maximum height, where v = 0 then ) s 00 . 4 ( s m 0 . 12 0 0 g gt v - = - 2 s m 00 . 3 = g Apply Newton’s second law to a falling object: G gR M R GmM mg ma F 2 2 : = = = π C R C πR 2 2 = = ( 29 kg 10 56 . 4 kg m N 10 67 . 6 ) s m 00 . 3 ( 25 2 2 11 2 2 m 10 00 . 2 2 2 8 × = × = = - × π G gR M b) Apply Newton’s second law to the orbiting starship. r mv r GmM ma F 2 2 : = = Σ GM r T T r v 3 2 4 2 π
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Unformatted text preview: = m 10 . 3 2 km 000 , 30 7 × + = + = C R r kg) 10 56 . 4 )( kg Nm 10 67 . 6 ( m) 10 . 3 ( 4 25 2 2 11 3 7 2 m 10 00 . 2 2 8 × × × + =-× T h 4 . 15 s 3600 h 1 s 10 54 . 5 4 = × =...
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• Trigraph, Kilogram, v= GmM mv

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