Using a Quadratic Equation Problems
A ball is thrown vertically upward from the top of a building 112 feet tall with an initial velocity of 96 feet per second.
(in feet) of the ball from the ground after
= 112 + 96t - 16t
Complete the table and discuss the interpretation of each point.
At zero seconds the ball was at its original height of 112ft.
At 0.5 seconds the ball would reach 156ft.
At 1 second the ball would reach 192ft
At 2 seconds the ball would reach 240ft.
The ball at 100ft will have two different y coordinates. The ball would reach 100ft at
-0.1225 seconds. If the ball was never thrown it would take 0.1225 to reach 12ft.
The ball at 100ft will have two different y coordinates. The ball would reach 100ft would
take 6.1225 seconds.
The ball will reach 200ft twice, once after thrown and on the decent. The ball would reach
200ft would take 1.1292 seconds.
The ball would reach 200ft twice again, once after thrown and on the decent. The ball