Module 4 - Using a Quadratic Equation Help_3.docx - Using a...

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Using a Quadratic Equation Problems A ball is thrown vertically upward from the top of a building 112 feet tall with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s (t) = 112 + 96t - 16t 2 Complete the table and discuss the interpretation of each point. t s(t) Interpretation 0 112 At zero seconds the ball was at its original height of 112ft. 0.5 156 At 0.5 seconds the ball would reach 156ft. 1 192 At 1 second the ball would reach 192ft 2 240 At 2 seconds the ball would reach 240ft. -0.1225 100 The ball at 100ft will have two different y coordinates. The ball would reach 100ft at -0.1225 seconds. If the ball was never thrown it would take 0.1225 to reach 12ft. 6.1225 100 The ball at 100ft will have two different y coordinates. The ball would reach 100ft would take 6.1225 seconds. 1.1292 200 The ball will reach 200ft twice, once after thrown and on the decent. The ball would reach 200ft would take 1.1292 seconds. 4.8708 200 The ball would reach 200ft twice again, once after thrown and on the decent. The ball

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