problem12_71

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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12.71: a) The stars are separated by the diameter of the circle d =2 R , so the gravitational force is . 2 2 4 R GM b) The gravitational force found in part (b) is related to the radial acceleration by R Mv Ma F 2 rad g = = for each star, and substituting the expression for the force from part (a) and solving for v gives . 4 R GM v = The period is . 4 16 2 3 3 2 2 GM R GM R R
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Unformatted text preview: π υ = = = Τ c) The initial gravitational potential energy is R GM 2 2-and the initial kinetic energy is , 4 . ) 2 1 ( 2 2 2 R GM Mv = so the total mechanical energy is . 2 2 R GM-If the stars have zero speed when they are very far apart, the energy needed to separate them is . 4 2 R GM...
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