**Unformatted text preview: **+ on the sphere, and the x-component of this force is ( 29 . 2 / 3 2 2 2 2 2 2 x a GmdMx x a x x a GmdM + = + + As x >> a the denominator approaches 2 and 3 x GMm F x → , as expected, and so the force on the sphere is ( 29 , / 2 / 3 2 2 x a GmMx + in the direction.-x-The sphere attracts the ring with a force of the same magnitude. (This is an alternative but equivalent way of obtaining the result of parts (c) and (d) of Exercise 12.39.)2...

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