problem12_82

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
12.82: The direct calculation of the force that the sphere exerts on the ring is slightly more involved than the calculation of the force that the ring exerts on the ball. These forces are equal in magnitude but opposite in direction, so it will suffice to do the latter calculation. By symmetry, the force on the sphere will be along the axis of the ring in Fig. (12.34), toward the ring. Each mass element dM of the ring exerts a force of magnitude 2 2 x a GmdM
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: + on the sphere, and the x-component of this force is ( 29 . 2 / 3 2 2 2 2 2 2 x a GmdMx x a x x a GmdM + = + + As x >> a the denominator approaches 2 and 3 x GMm F x → , as expected, and so the force on the sphere is ( 29 , / 2 / 3 2 2 x a GmMx + in the direction.-x-The sphere attracts the ring with a force of the same magnitude. (This is an alternative but equivalent way of obtaining the result of parts (c) and (d) of Exercise 12.39.)2...
View Full Document

This document was uploaded on 02/05/2008.

Ask a homework question - tutors are online