Math 112 4.6 Notes

# Math 112 4.6 Notes - Section 4.6 Population Growth P(t P0 e...

This preview shows pages 1–4. Sign up to view the full content.

Section 4.6 Population Growth: t k e P t P * 0 ) ( = P 0 is the initial population k is the exponential growth rate t is the time in years P(t) is the population after t years Example 1: The population of a city was 94,000 in 1992. The exponential growth rate is 1.7% per year. a.) Find the exponential growth function where t is the number of years since 1992. b.) What is the population in 2008? c.) In what year will the population be 105,000?

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Doubling Time: The doubling time is the time it takes for P(t) = 2*P 0 . Similarly, the tripling time is the time it takes for P(t) = 3*P 0 . Example 1: If the exponential growth rate is 1.7% per year, what is the doubling time? Example 2: Find the exponential growth rate if the doubling time is 43 years.
Continuously Compounded Interest: t r e P A * * = A is the amount in the account P is the principle or amount invested r is the interest rate per year t is the time in years Example 1: If \$9000 is invested at 5% interest compounded continuously for 7 years. a.) What will be the amount of money in the

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 6

Math 112 4.6 Notes - Section 4.6 Population Growth P(t P0 e...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online