Quiz 02-01 soln

50 m and 2 150 m thelengthoftheshadowisxlxisgivenby x

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Unformatted text preview: rees. Then consider a ray that grazes the top of the pole, as shown in the diagram below. . (In the diagram, 1 = 35°, 1 0.50 m, and 2 150 m. ) The length of the shadow is x + L. x is given by x 1 tan 1 (0.50 m) tan 35 0.35 m. Next, to find L according to the law of refraction, n2 sin 2 = n1 sin 1. We take n1 = 1 and n2 = 1.33. Then, 2 sin 1 FG sin IJ sin FG sin 35.0 IJ 2555 . H 133 K . . Hn K 1 1 2 The distance L is given by L 2 tan 2 (150 m) tan 25.55 0.72 m. . The length of the shadow is 0.35 m + 0.72 m = 1.07 m....
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