183503 and t 10816497 t p t 8 0 9183503 5088662

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Unformatted text preview: 23 − 16 = 7 hundred entries (d) P′( t ) = 0 when t = 9.183503 and t = 10.816497. t P (t ) 8 0 9.183503 5.088662 10.816497 2.911338 12 8 Entries are being processed most quickly at time t = 12. 1 : answer ⎧ 1 : trapezoidal sum ⎪ 3 : ⎨ 1 : approximation ⎪ 1 : meaning ⎩ 2: { 1 : integral 1 : answer ⎧ 1 : considers P′( t ) = 0 ⎪ 3 : ⎨ 1 : identifies candidates ⎪ 1 : answer with justification ⎩ © 2010 The College Board. Visit the College Board on the Web: www.collegeboard.com. © 2010 The College Board. Visit the College Board on the Web: www.collegeboard.com. © 2010 The College Board. Visit the College Board on the Web: www.collegeboard.com. © 2010 The College Board. Visit the College Board on the Web: www.collegeboard.com. © 2010 The College Board. Visit the College Board on the Web: www.collegeboard.com. © 2010 The College Board. Visit the College Board on the Web: www.collegeboard.com. © 2010 The College Board. Visit the College Board on the Web: www.collegeboard.com. AP® CALCULUS BC 2010 SCORING COMMENTARY Question 2 Overview This problem involved a zoo’s contest to name a baby elephant. Students were presented with a table of values indicating the number of entries E ( t ) , measured in hundreds, received in a special box and recorded at various times t during an eight-hour period. Part (a) asked for an estimate of the rate of deposit of entries into the box at time t = 6. Students needed to recognize this rate to be the derivative value E ′( 6 ) . Since t = 6 falls between the time values specified in the table, students needed to calculate the average rate of change of E across the smallest 18 time subinterval from the table that brackets t = 6. Part (b) asked for an approximation to E ( t...
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This note was uploaded on 08/22/2013 for the course CALCULUS AP taught by Professor Staff during the Fall '11 term at Lakota West High School.

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