problem13_23

# University Physics with Modern Physics with Mastering Physics (11th Edition)

• Homework Help
• PresidentHackerCaribou10582
• 1

This preview shows page 1. Sign up to view the full content.

13.23: a) Setting 2 2 1 2 2 1 kx mv = in Eq. (13.21) and solving for x gives . 2 A x ± = Eliminating x in favor of v with the same relation gives . 2 2 2 ωA x m kA v ± = ± = b) This happens four times each cycle, corresponding the four possible combinations of + and –
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: in the results of part (a). The time between the occurrences is one-fourth of a period or ( 29 8 3 8 4 3 4 1 2 4 2 2 2 , , c) . 4 / kA kA ω π ω π K U E K E U T = = = = = =...
View Full Document

• '
• NoProfessor
• kx, possible combinations, Ford Ka

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern