problem13_24

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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13.24: a) From Eq. (13.23), m/s. 1.20 m) 040 . 0 ( kg 0.500 m N 450 max = = = A m k v b) From Eq. (13.22), m/s. 11 . 1 m) 015 . 0 ( m) 040 . 0 ( kg 0.500 N 450 2 2 = - - = v c) The extremes of acceleration occur at the extremes of motion, when , A x ± = and 2 max m/s 36 kg) (0.500 m) N/m)(0.040
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Unformatted text preview: 450 ( = = = m kA a d) From Eq. (13.4), . m/s 5 . 13 2 kg) (0.500 m) 0.015 N/m)( 450 ( =-=-x a e) From Eq. (13.31), J. 36 . m) N/m)(0.040 450 ( 2 2 1 = = E...
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• kg, m/s, Eq., Metre per second squared

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