Units 7 2xy dx dy 0 1 1 i 003 100 points 2

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: value of the iterated integral 3 2 I= I = 72 cu. units . (7 + 2xy ) dx dy . 0 1 1. I = 003 10.0 points 2. I = 57 2 3. I = 65 2 4. I = keywords: double integral, linear function, volume under graph, volume, rectangular region, prism, triangle 53 2 61 2 5. I = 69 correct 2 Find the value of the integral 2 I= f (x, y ) dx 0 when f (x, y ) = x − 4x2 y . 1. I = 2 + 32 2 y 3 Explanation: Integrating with respect to x and holding y fixed, we see that 2 (7 + 2xy ) dx = 1 2. I = 2 − 4y 3. I = y − 4y 7 x + x2 y x=2 x=1 . Thus 2 4. I = y − 16y 2 5. I = 2 + 32 y 3 6. I = 2 − 32 y correct 3 3 I= (7 + 3y ) dy = 0 3 7y + y 2 2 Consequently, I = 21 + 27 69 . = 2 2 3 0 . chester (crc2876) – HW13 – meth – (91845) 3 keywords: 006 005 10.0 points 10.0 points Evaluate the iterated integral Evaluate the double integral 3 4 I= I= A 1 (2x − 3y ) dxdy 0 1. I = ln when A= (x, y )...
View Full Document

This note was uploaded on 08/25/2013 for the course MATH 408M taught by Professor Kushner during the Summer '10 term at University of Texas at Austin.

Ask a homework question - tutors are online