Chem 14.1-14.3

Manipula2ons of k and reac2ons a b k ba if you

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Unformatted text preview: brium point lies to the right The products are present in higher concentra2ons than reactants, so the equilibrium is said to “lie to the right (products)” The following boxes represent reacAons of the type A B at equilibrium. In which of the following is Keq = 2? A B Reac(on I 1) ReacAon I 2) ReacAon II 3) ReacAon III 4) All have Keq = 2 5) None have Keq = 2 Reac(on II Reac(on III The following boxes represent reacAons of the type A B at equilibrium. In which of the following is Keq = 2? A B Reac(on I 1) ReacAon I 2) Reac)on II 3) ReacAon III 4) All have Keq = 2 5) None have Keq = 2 Reac(on II Reac(on III Manipula2ons of K and reac2ons A B K = [B]/[A] Manipula2ons of K and reac2ons A B K = [B]/[A] • If you reverse the reacAon? Manipula2ons of K and reac2ons A B K = [B]/[A] • If you reverse the reacAon? – B A Kreverse = [A]/[B] Manipula2ons of K and reac2ons A B K = [B]/[A] • If you reverse the reacAon? – B A Kreverse = [A]/[B] – Take the inverse of Kforward Manipula2ons of K and reac2ons A B K = [B]/[A] • If you reverse the reacAon? – B A Kreverse = [A]/[B] – Take the inverse of Kforward • If you mulAply the reacAon by 2 (or any other number)? Manipula2ons of K and...
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This note was uploaded on 08/23/2013 for the course CHEM 152 taught by Professor Carriemiller during the Spring '13 term at Azusa Pacific.

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