problem13_28

University Physics with Modern Physics with Mastering Physics (11th Edition)

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13.28: At the time in question we have 2 2 s m 40 . 8 ) ( cos s m 20 . 2 ) sin( m 600 . 0 ) ( cos - = + - = = + - = = + = φ ωt A ω a ωt ωA v ωt A x Using the displacement and acceleration equations: 2 2 2 s m 40 . 8 m) 600 . 0 ( ) ( cos - = - = + - ω ωt A ω 1 2 s 742 . 3 and 0 . 14 - = = ω ω To find A , multiply the velocity equation by : ω 2 1 2 s m 232 . 8 ) s m (2.20 ) s 742 . 3 ( ) ( sin = = + - - ωt A ω Next square both this new equation and the acceleration equation and add them: m 840 . 0 m 7054 . 0 ) s 742 . 3 ( s m 3 . 138 s m 3 . 138 s m 3 . 138 s m 56 . 70 s m 77 . 67 ) ( cos ) ( sin ) s m 40 . 8 ( ) s m 232 . 8 ( ) ( cos ) ( sin
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