problem13_57

University Physics with Modern Physics with Mastering Physics (11th Edition)

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13.57: a) . s m 10 72 . 6 min rev s rad 30 ) min rev 3500 ( 2 m 100 . 0 2 3 2 2 × = = = π a b) . s m 3 . 18 min rev s rad 30 ) m 05 (. ) min rev 3500 ( c) N. 10 02 . 3 3 = = × = π ωA ma J. 6 . 75 ) s m 3 . 18 )( kg 45 )(. ( 2 2 1 2 2 1 = = = mv K d) At the midpoint of the stroke, cos( ω t )=0 and so s, rad ) )( min rev (3500 2 thus , 2 3 350 min rev s rad 30 π π ω. ω π t π ωt = = = = so W. 10 1.76 s) ( J 6 . 75 or , Then s. 4 2(350) 3 ) 350 ( 2 3 × = = = = P t K P t e) If the frequency doubles, the acceleration and hence the needed force will quadruple (12.1 N). 10 3 × The maximum speed increases by a factor of 2 since
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