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10 All expected counts are greater than or equal to 5 (or 10), so it is OK to proceed with the
chisquare test.
Part 3: Correct mechanics.
ChiSq = 0.667
0.017
1.190
DF = 5, PValue + 0.667 + 0.373 +
+ 0.017 + 4.263 +
+ 1.190 + 0.400 +
= 0.017 0.373 +
4.263 +
0.400 = 13.821 Part 4: States a correct conclusion in context using the result of the statistical test.
Because the Pvalue < α (problem states α = .10), reject H0. There is convincing
evidence that the distribution of number of lab classes is not the same in 2000 as it
was in 1990. Copyright © 2002 by College Entrance Examination Board. All rights reserved.
Advanced Placement Program and AP are registered trademarks of the College Entrance Examination Board. 20 AP® STATISTICS
2002 SCORING GUIDELINES (Form B)
Question 6 (cont’d.)
Part (c):
Although the two distributions are centered in about the same place, the shape of the
distributions is different. In 2000, the proportion of students taking three labs was
smaller than in 1...
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 Spring '13
 Mosby
 Statistics, AP Statistics

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