At the x ke dl a b de sin ke dl de y y z

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Unformatted text preview:   From determining the differential electric field and integrating we find 0   From symmetry we could have also seen that the net field in the y-direction must π be 0 kλ Ey = − θ E d R dq=λdl d y dl Physics 2B - Summer Session 2 - C. Palmer ∫ 2 π − 2 y x sin (θ ) dθ = 0 Charge Density +λ (C/m) August 7, 2013 9 If only half of the line of charge is infinite, what would the total field in the ydirection be? kE λ A) B) Ey = − Ey = 0 C) kE λ Ey = d θ D) R x y d kE λ Ey = 2 d Charge dq=λdl d y z dl Physics 2B - Summer Session 2 - C. Palmer Density +λ (C/m) August 7, 2013 10 If only half of the line of charge is infinite, what would the total field in the ydirection be? kE λ A) B) Ey = − Ey = 0 C) kE λ Ey = d θ D) R x y d kE λ Ey = 2 d Charge dq=λdl d y z dl Physics 2B - Summer Session 2 - C. Palmer Density +λ (C/m) August 7, 2013 11 z   There is a ring of charge, Q, in the z=0 plane.   Above the center of the ring at distance z, we x would like to know the value of the electric field.   The ring has radius, R0. R y z R0 Physics 2B - Summer Session 2 - C. Palmer August 7, 2013 12 z The ring has radius, R0. What is the charge density of the ring? A) QC σ= 2 2 π R0 m C) QC λ= 2π R0 m x y B) QC σ= π R2 m 2 D) QC λ= 2π R m Physics 2B - Summer Session 2 - C. Palmer R z R0 August 7, 2013 13 z The ring has radius, R0. What is the charge density of the ring? A) QC σ= 2 2 π R0 m C) QC λ= 2π R0 m x y B) QC σ= π R2 m 2 D) QC λ= 2π R m Physics 2B - Summer Session 2 - C. Palmer R z R0 August 7, 2013 14 z   There is a ring of charge, Q, in the z=0 plane.   The ring has radius, R0. x dEz y dE dER   The dE has been added.   Think about what is going on with the radial component. θ R dq=λdl Physics 2B - Summer Session 2 - C. Palmer z R0 August 7, 2013 15 z   There is a ring of charge, Q, in the z=0 plane.   The ring has radius, R0. x dEz dE dER   The dE has been added.   The radial component will sum to zero because there will be complementary θ piece opposite it. R   Again we only need to worry about the zcomponent dq=λdl y z R0 Physics 2B - Summer Session 2 - C. Palmer August 7, 2013 16 z   There is a ring of charge, Q, in the z=0 plane.   The ring has radius, R0. x dEz dE dER   Set up dEz quantitatively kE dq dEz = cos (θ ) 2 R kE dq = cos (θ ) 2 2 R0 + z y θ R dq=λdl Physics 2B - Summer Session 2 - C. Palmer z R0 August 7, 2013 17 z   There is a ring of charge, Q, in the z=0 plane.   The ring has radius, R0. x dEz dE dER   Set up dEz quantitatively kE dq dEz = cos (θ ) 2 2 R0 + z z kE dq = 2 2 R2 + z2 R0 + z 0 dq=λdl P...
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This note was uploaded on 09/10/2013 for the course PHYS 2B 2b taught by Professor Hirsch during the Summer '10 term at UCSD.

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