A left b right qv b c up d

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Unformatted text preview: ith velocity, v, to the right. What is the magnitude and direction of the resulting magnetic force if |B0|=4T and |v|=3e5m/s? Recall e=1.6e-19C y A)  1.92e-13 N in the y dir B)  1.92e-8 N in the y dir z x - C)  1.92e-13 N in the – y dir D)  1.92e-8 N in the – y dir Physics 2B - Summer Session 2 - C. Palmer August 21, 2013 18 There is a uniform magnetic field going out of the page with strength, B0, in the z direction. An electron is moving with velocity, v, to the right. What is the magnitude and direction of the resulting magnetic force if |B0|=4T and |v|=3e5m/s? Recall e=1.6e-19C y A)  1.92e-13 N in the y dir B)  1.92e-8 N in the y dir z x - C)  1.92e-13 N in the – y dir D)  1.92e-8 N in the – y dir Physics 2B - Summer Session 2 - C. Palmer August 21, 2013 19   Review the motion of a +y charge in a uniform ELECTRIC field FE = qE +x + Physics 2B - Summer Session 2 - C. Palmer August 21, 2013 20   Review the motion of a +y charge in a uniform ELECTRIC field FE = qE +   Apply Newton’s 2nd law of FE +x motion ∑ F i = ma Physics 2B - Summer Session 2 - C. Palmer August 21, 2013 21   Review the motion of a +y charge in a uniform ELECTRIC field   Apply Newton’s 2nd law of motion ˆ qE = qE0 x = ma Physics 2B - Summer Session 2 - C. Palmer + August 21, 2013 FE +x 22   Review the motion of a +y charge in a uniform ELECTRIC field   Apply Newton’s 2nd law of motion ˆ qE = qE0 x = ma + FE +x qE0 ˆ ⇒a= x m Physics 2B - Summer Session 2 - C. Palmer August 21, 2013 23   Work done by the field +y F ⋅ ds W =∫ x2 ˆˆ = qE0 ∫ x ⋅ x dx + FE +x x1 >0 Physics 2B - Summer Session 2 - C. Palmer August 21, 2013 24   We can use the RHR to determine the force direction ˆ ˆ v = vx; B = B0 z y z Physics 2B - Summer Session 2 - C. Palmer x + August 21, 2013 25   We can use the RHR to determine the force direction ˆ ˆ v = vx; B = B0 z y FB = qv × B z x + ˆ = qvB0 ( − y ) Physics 2B - Summer Session 2 - C. Palmer August 21, 2013 FB 26 ˆ FB = qv × B = qvB0 ( − y )   After a small amount of time the charge moves like so. +   Notice the force and + motion are ALWAYS perpendicular y z x Physics 2B - Summer Session 2 - C. Palmer August 21, 2013 27 ˆ FB = qv × B = qvB0 ( − y )   After a small amount of time the charge moves + Physics 2B - Summer Session 2 - C. Palmer + motion are ALWAYS perpendicular   The acceleration is always toward the y center. x z +   Notice the force and + like so. August 21, 2013 28   The acceleration is always toward the center. y   Circular z   Again apply Newton’s 2nd law ∑ Fi = ma x...
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This note was uploaded on 09/10/2013 for the course PHYS 2B 2b taught by Professor Hirsch during the Summer '10 term at UCSD.

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